Matematika Sekolah Menengah Atas 1) Tuliskan operasi bilangan dibawah ini menjadi bentuk perpangkatan:
a)2×2×2=
b)1/3×1/3×1/3×1/3=

2) Hitunglah hasil dari operasi bilangan berpangkat berikut ini dengan menggunakan sifat-sifat perpangkatan yang berlaku:
a)10²×10³=
b)5⁸×5⁶=
c)(8⁰)⁵=

1) Tuliskan operasi bilangan dibawah ini menjadi bentuk perpangkatan:
a)2×2×2=
b)1/3×1/3×1/3×1/3=

2) Hitunglah hasil dari operasi bilangan berpangkat berikut ini dengan menggunakan sifat-sifat perpangkatan yang berlaku:
a)10²×10³=
b)5⁸×5⁶=
c)(8⁰)⁵=

Jawaban:

1. a. 2³

b. 1/3⁴

2. a. 10×10 × 10×10×10

100 × 1.000

= 100.000 = 10^5

b. 5×5×5×5×5×5×5×5 × 5×5×5×5×5×5

390.625 × 15.625

= 406.250 =

c. (8^0) ^5 = 1

Penjelasan dengan langkah-langkah:

semoga membantu

[tex] \mathbb{ \color{aqua}{ \underbrace{JAWABAN}}}[/tex]

SOAL 1 :

  • a) 2³
  • b) ()

SOAL 2 :

  • a) 100.000
  • b) 6.103.515.625
  • c) 1

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[tex] \mathbb{ \color{orange}{ \underbrace{PENYELESAIAN}}}[/tex]

[tex] \boxed{ \: \tt{a}^{n} \to \underbrace{\tt{a \times a \times a \times ... \times a}}_{\tt{sebanyak ~n ~faktor}} \: } \\ \\ [/tex]

SOAL 1a :

[tex] \boxed{ \: \begin{aligned} \tt{2 \times 2 \times 2} &= \red{ \boxed{ \bf{ \pink{ {2}^{3}} }}} \end{aligned} \: } \\ \\ [/tex]

SOAL 1b :

[tex] \boxed{ \: \begin{aligned} \tt{ \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} } &= \red{ \boxed{ \bf{ \pink{{ \left( \frac{1}{3} \right)}^{4} } }}} \end{aligned} \: } \\ \\ [/tex]

[tex]\color{ff0000}{–} \color{ff4000}{–}\color{ff8000}{–}\color{ffc000}{–}\color{ffff00}{–}\color{c0ff00}{–}\color{80ff00}{–}\color{40ff00}{–}\color{00ff00}{–}\color{00ff40}{–}\color{00ff80}{–}\color{00ffc0}{–}\color{00ffff}{–}\color{00c0ff}{–}\color{0080ff}{–}\color{0040ff}{–}\color{0000ff}{–}\color{4000ff}{–}\color{8000ff}{–}\color{c000ff}{–}\color{ff00ff}{–}\color{ff00c0}{–}\color{ff00a0}{–}\color{ff0080}{–}\color{ff0040}{–} \\ \\ [/tex]

[tex] \begin{aligned} &\begin{aligned} \small{ \bf{ \blue{Gunakan \: sifat - sifat \: eksponen \: berikut : }}} \end{aligned} \\ &\boxed{ \: \begin{aligned} \tt{ {a}^{m} \times {a}^{n} } &= \tt{ {a}^{m + n} } \\ \tt{ {( {a}^{m} )}^{n} }&= \tt{ {a}^{m \times n} } \\ \tt{ {a}^{0} }&= \tt{1} \end{aligned} \: } \end{aligned} \\ \\ [/tex]

SOAL 2a :

[tex] \boxed{ \: \begin{aligned} \tt{ {10}^{2} \times {10}^{3} } &= \tt{ {10}^{2 + 3} } \\ &= \tt{ {10}^{5} } \\ &= \red{ \boxed{ \bf{ \pink{100.000}}}} \end{aligned} \: } \\ \\ [/tex]

SOAL 2b :

[tex] \boxed{ \: \begin{aligned} \tt{ {5}^{8} \times {5}^{6} } &= \tt{ {5}^{8 + 6} } \\ &= \tt{ {5}^{14} } \\ &= \red{ \boxed{ \bf{ \pink{6.103.515.625}}}} \end{aligned} \: } \\ \\ [/tex]

SOAL 2c :

[tex] \boxed{ \: \begin{aligned} \tt{ {( {8}^{0} )}^{5} } &= \tt{ {8}^{0 \times 5} } \\ &= \tt{ {8}^{0} } \\ &= \red{ \boxed{ \bf{ \pink{1}}}} \end{aligned} \: }[/tex]

[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} [/tex]

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